x^2+120x-17800=0

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Solution for x^2+120x-17800=0 equation:



x^2+120x-17800=0
a = 1; b = 120; c = -17800;
Δ = b2-4ac
Δ = 1202-4·1·(-17800)
Δ = 85600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{85600}=\sqrt{400*214}=\sqrt{400}*\sqrt{214}=20\sqrt{214}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-20\sqrt{214}}{2*1}=\frac{-120-20\sqrt{214}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+20\sqrt{214}}{2*1}=\frac{-120+20\sqrt{214}}{2} $

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